1016. Binary String With Substrings Representing 1 To N

Description

Given a binary string s and a positive integer n, return true if the binary representation of all the integers in the range [1, n] are substrings of s, or false otherwise.

A substring is a contiguous sequence of characters within a string.

 

Example 1:

Input: s = "0110", n = 3
Output: true

Example 2:

Input: s = "0110", n = 4
Output: false

 

Constraints:

  • 1 <= s.length <= 1000
  • s[i] is either '0' or '1'.
  • 1 <= n <= 109

Solutions

Solution 1

Python Code
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class Solution:
    def queryString(self, s: str, n: int) -> bool:
        if n > 1000:
            return False
        return all(bin(i)[2:] in s for i in range(n, n // 2, -1))

Java Code
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class Solution {
    public boolean queryString(String s, int n) {
        if (n > 1000) {
            return false;
        }
        for (int i = n; i > n / 2; i--) {
            if (!s.contains(Integer.toBinaryString(i))) {
                return false;
            }
        }
        return true;
    }
}

C++ Code
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class Solution {
public:
    bool queryString(string s, int n) {
        if (n > 1000) {
            return false;
        }
        for (int i = n; i > n / 2; --i) {
            string b = bitset<32>(i).to_string();
            b = b.substr(b.find_first_not_of('0'));
            if (s.find(b) == string::npos) {
                return false;
            }
        }
        return true;
    }
};

Go Code
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func queryString(s string, n int) bool {
	if n > 1000 {
		return false
	}
	for i := n; i > n/2; i-- {
		if !strings.Contains(s, strconv.FormatInt(int64(i), 2)) {
			return false
		}
	}
	return true
}

TypeScript Code
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function queryString(s: string, n: number): boolean {
    if (n > 1000) {
        return false;
    }
    for (let i = n; i > n / 2; --i) {
        if (s.indexOf(i.toString(2)) === -1) {
            return false;
        }
    }
    return true;
}