1424. Diagonal Traverse II

Description

Given a 2D integer array nums, return all elements of nums in diagonal order as shown in the below images.

 

Example 1:

Input: nums = [[1,2,3],[4,5,6],[7,8,9]]
Output: [1,4,2,7,5,3,8,6,9]

Example 2:

Input: nums = [[1,2,3,4,5],[6,7],[8],[9,10,11],[12,13,14,15,16]]
Output: [1,6,2,8,7,3,9,4,12,10,5,13,11,14,15,16]

 

Constraints:

  • 1 <= nums.length <= 105
  • 1 <= nums[i].length <= 105
  • 1 <= sum(nums[i].length) <= 105
  • 1 <= nums[i][j] <= 105

Solutions

Solution 1

Python Code
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class Solution:
    def findDiagonalOrder(self, nums: List[List[int]]) -> List[int]:
        arr = []
        for i, row in enumerate(nums):
            for j, v in enumerate(row):
                arr.append((i + j, j, v))
        arr.sort()
        return [v[2] for v in arr]

Java Code
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class Solution {
    public int[] findDiagonalOrder(List<List<Integer>> nums) {
        List<int[]> arr = new ArrayList<>();
        for (int i = 0; i < nums.size(); ++i) {
            for (int j = 0; j < nums.get(i).size(); ++j) {
                arr.add(new int[] {i + j, j, nums.get(i).get(j)});
            }
        }
        arr.sort((a, b) -> a[0] == b[0] ? a[1] - b[1] : a[0] - b[0]);
        int[] ans = new int[arr.size()];
        for (int i = 0; i < arr.size(); ++i) {
            ans[i] = arr.get(i)[2];
        }
        return ans;
    }
}

C++ Code
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class Solution {
public:
    vector<int> findDiagonalOrder(vector<vector<int>>& nums) {
        vector<tuple<int, int, int>> arr;
        for (int i = 0; i < nums.size(); ++i) {
            for (int j = 0; j < nums[i].size(); ++j) {
                arr.push_back({i + j, j, nums[i][j]});
            }
        }
        sort(arr.begin(), arr.end());
        vector<int> ans;
        for (auto& e : arr) {
            ans.push_back(get<2>(e));
        }
        return ans;
    }
};

Go Code
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func findDiagonalOrder(nums [][]int) []int {
	arr := [][]int{}
	for i, row := range nums {
		for j, v := range row {
			arr = append(arr, []int{i + j, j, v})
		}
	}
	sort.Slice(arr, func(i, j int) bool {
		if arr[i][0] == arr[j][0] {
			return arr[i][1] < arr[j][1]
		}
		return arr[i][0] < arr[j][0]
	})
	ans := []int{}
	for _, v := range arr {
		ans = append(ans, v[2])
	}
	return ans
}

C# Code
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public class Solution {
    public int[] FindDiagonalOrder(IList<IList<int>> nums) {
        List<int[]> arr = new List<int[]>();
        for (int i = 0; i < nums.Count; ++i) {
            for (int j = 0; j < nums[i].Count; ++j) {
                arr.Add(new int[] { i + j, j, nums[i][j] });
            }
        }
        arr.Sort((a, b) => a[0] == b[0] ? a[1] - b[1] : a[0] - b[0]);
        int[] ans = new int[arr.Count];
        for (int i = 0; i < arr.Count; ++i) {
            ans[i] = arr[i][2];
        }
        return ans;
    }
}