181. Employees Earning More Than Their Managers

Description

Table: Employee

+-------------+---------+
| Column Name | Type    |
+-------------+---------+
| id          | int     |
| name        | varchar |
| salary      | int     |
| managerId   | int     |
+-------------+---------+
id is the primary key (column with unique values) for this table.
Each row of this table indicates the ID of an employee, their name, salary, and the ID of their manager.

 

Write a solution to find the employees who earn more than their managers.

Return the result table in any order.

The result format is in the following example.

 

Example 1:

Input: 
Employee table:
+----+-------+--------+-----------+
| id | name  | salary | managerId |
+----+-------+--------+-----------+
| 1  | Joe   | 70000  | 3         |
| 2  | Henry | 80000  | 4         |
| 3  | Sam   | 60000  | Null      |
| 4  | Max   | 90000  | Null      |
+----+-------+--------+-----------+
Output: 
+----------+
| Employee |
+----------+
| Joe      |
+----------+
Explanation: Joe is the only employee who earns more than his manager.

Solutions

Solution 1

Python Code
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import pandas as pd


def find_employees(employee: pd.DataFrame) -> pd.DataFrame:
    df = employee.merge(right=employee, how="left", left_on="managerId", right_on="id")
    emp = df[df["salary_x"] > df["salary_y"]]["name_x"]

    return pd.DataFrame({"Employee": emp})

SQL Code
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SELECT Name AS Employee
FROM Employee AS Curr
WHERE
    Salary > (
        SELECT Salary
        FROM Employee
        WHERE Id = Curr.ManagerId
    );

Solution 2

SQL Code
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# Write your MySQL query statement below
SELECT
    e1.name AS Employee
FROM
    Employee AS e1
    JOIN Employee AS e2 ON e1.managerId = e2.id
WHERE e1.salary > e2.salary;