2089. Find Target Indices After Sorting Array

Description

You are given a 0-indexed integer array nums and a target element target.

A target index is an index i such that nums[i] == target.

Return a list of the target indices of nums after sorting nums in non-decreasing order. If there are no target indices, return an empty list. The returned list must be sorted in increasing order.

 

Example 1:

Input: nums = [1,2,5,2,3], target = 2
Output: [1,2]
Explanation: After sorting, nums is [1,2,2,3,5].
The indices where nums[i] == 2 are 1 and 2.

Example 2:

Input: nums = [1,2,5,2,3], target = 3
Output: [3]
Explanation: After sorting, nums is [1,2,2,3,5].
The index where nums[i] == 3 is 3.

Example 3:

Input: nums = [1,2,5,2,3], target = 5
Output: [4]
Explanation: After sorting, nums is [1,2,2,3,5].
The index where nums[i] == 5 is 4.

 

Constraints:

  • 1 <= nums.length <= 100
  • 1 <= nums[i], target <= 100

Solutions

Solution 1

Python Code
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class Solution:
    def targetIndices(self, nums: List[int], target: int) -> List[int]:
        nums.sort()
        return [i for i, v in enumerate(nums) if v == target]

Java Code
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class Solution {
    public List<Integer> targetIndices(int[] nums, int target) {
        Arrays.sort(nums);
        List<Integer> ans = new ArrayList<>();
        for (int i = 0; i < nums.length; ++i) {
            if (nums[i] == target) {
                ans.add(i);
            }
        }
        return ans;
    }
}

C++ Code
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class Solution {
public:
    vector<int> targetIndices(vector<int>& nums, int target) {
        sort(nums.begin(), nums.end());
        vector<int> ans;
        for (int i = 0; i < nums.size(); ++i) {
            if (nums[i] == target) {
                ans.push_back(i);
            }
        }
        return ans;
    }
};

Go Code
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func targetIndices(nums []int, target int) (ans []int) {
	sort.Ints(nums)
	for i, v := range nums {
		if v == target {
			ans = append(ans, i)
		}
	}
	return
}

TypeScript Code
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function targetIndices(nums: number[], target: number): number[] {
    nums.sort((a, b) => a - b);
    let ans: number[] = [];
    for (let i = 0; i < nums.length; ++i) {
        if (nums[i] == target) {
            ans.push(i);
        }
    }
    return ans;
}