Description#
The Hamming distance between two integers is the number of positions at which the corresponding bits are different.
Given two integers x
and y
, return the Hamming distance between them.
Example 1:
Input: x = 1, y = 4
Output: 2
Explanation:
1 (0 0 0 1)
4 (0 1 0 0)
↑ ↑
The above arrows point to positions where the corresponding bits are different.
Example 2:
Input: x = 3, y = 1
Output: 1
Constraints:
Solutions#
Solution 1#
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| class Solution:
def hammingDistance(self, x: int, y: int) -> int:
return (x ^ y).bit_count()
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| class Solution {
public int hammingDistance(int x, int y) {
return Integer.bitCount(x ^ y);
}
}
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| class Solution {
public:
int hammingDistance(int x, int y) {
return __builtin_popcount(x ^ y);
}
};
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| func hammingDistance(x int, y int) int {
return bits.OnesCount(uint(x ^ y))
}
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| function hammingDistance(x: number, y: number): number {
x ^= y;
let ans = 0;
while (x) {
x -= x & -x;
++ans;
}
return ans;
}
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| /**
* @param {number} x
* @param {number} y
* @return {number}
*/
var hammingDistance = function (x, y) {
x ^= y;
let ans = 0;
while (x) {
x -= x & -x;
++ans;
}
return ans;
};
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