Description#
Given an array of points
where points[i] = [xi, yi]
represents a point on the X-Y plane and an integer k
, return the k
closest points to the origin (0, 0)
.
The distance between two points on the X-Y plane is the Euclidean distance (i.e., √(x1 - x2)2 + (y1 - y2)2
).
You may return the answer in any order. The answer is guaranteed to be unique (except for the order that it is in).
Example 1:
![](https://spcdn.pages.dev/leetcode/problems/0973.K%20Closest%20Points%20to%20Origin/images/closestplane1.jpg)
Input: points = [[1,3],[-2,2]], k = 1
Output: [[-2,2]]
Explanation:
The distance between (1, 3) and the origin is sqrt(10).
The distance between (-2, 2) and the origin is sqrt(8).
Since sqrt(8) < sqrt(10), (-2, 2) is closer to the origin.
We only want the closest k = 1 points from the origin, so the answer is just [[-2,2]].
Example 2:
Input: points = [[3,3],[5,-1],[-2,4]], k = 2
Output: [[3,3],[-2,4]]
Explanation: The answer [[-2,4],[3,3]] would also be accepted.
Constraints:
1 <= k <= points.length <= 104
-104 <= xi, yi <= 104
Solutions#
Solution 1#
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| class Solution:
def kClosest(self, points: List[List[int]], k: int) -> List[List[int]]:
points.sort(key=lambda p: p[0] * p[0] + p[1] * p[1])
return points[:k]
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| class Solution {
public int[][] kClosest(int[][] points, int k) {
Arrays.sort(points, (a, b) -> {
int d1 = a[0] * a[0] + a[1] * a[1];
int d2 = b[0] * b[0] + b[1] * b[1];
return d1 - d2;
});
return Arrays.copyOfRange(points, 0, k);
}
}
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| class Solution {
public:
vector<vector<int>> kClosest(vector<vector<int>>& points, int k) {
sort(points.begin(), points.end(), [](const vector<int>& a, const vector<int>& b) {
return a[0] * a[0] + a[1] * a[1] < b[0] * b[0] + b[1] * b[1];
});
return vector<vector<int>>(points.begin(), points.begin() + k);
}
};
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| func kClosest(points [][]int, k int) [][]int {
sort.Slice(points, func(i, j int) bool {
a, b := points[i], points[j]
return a[0]*a[0]+a[1]*a[1] < b[0]*b[0]+b[1]*b[1]
})
return points[:k]
}
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| function kClosest(points: number[][], k: number): number[][] {
return points.sort((a, b) => a[0] ** 2 + a[1] ** 2 - (b[0] ** 2 + b[1] ** 2)).slice(0, k);
}
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| impl Solution {
pub fn k_closest(mut points: Vec<Vec<i32>>, k: i32) -> Vec<Vec<i32>> {
points.sort_unstable_by(|a, b| {
(a[0].pow(2) + a[1].pow(2)).cmp(&(b[0].pow(2) + b[1].pow(2)))
});
points[0..k as usize].to_vec()
}
}
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