Description#
A sentence is a list of words that are separated by a single space with no leading or trailing spaces.
You are given an array of strings sentences
, where each sentences[i]
represents a single sentence.
Return the maximum number of words that appear in a single sentence.
Example 1:
Input: sentences = ["alice and bob love leetcode", "i think so too", "this is great thanks very much"]
Output: 6
Explanation:
- The first sentence, "alice and bob love leetcode", has 5 words in total.
- The second sentence, "i think so too", has 4 words in total.
- The third sentence, "this is great thanks very much", has 6 words in total.
Thus, the maximum number of words in a single sentence comes from the third sentence, which has 6 words.
Example 2:
Input: sentences = ["please wait", "continue to fight", "continue to win"]
Output: 3
Explanation: It is possible that multiple sentences contain the same number of words.
In this example, the second and third sentences (underlined) have the same number of words.
Constraints:
1 <= sentences.length <= 100
1 <= sentences[i].length <= 100
sentences[i]
consists only of lowercase English letters and ' '
only.sentences[i]
does not have leading or trailing spaces.- All the words in
sentences[i]
are separated by a single space.
Solutions#
Solution 1#
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| class Solution:
def mostWordsFound(self, sentences: List[str]) -> int:
return 1 + max(s.count(' ') for s in sentences)
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| class Solution {
public int mostWordsFound(String[] sentences) {
int ans = 0;
for (var s : sentences) {
int cnt = 1;
for (int i = 0; i < s.length(); ++i) {
if (s.charAt(i) == ' ') {
++cnt;
}
}
ans = Math.max(ans, cnt);
}
return ans;
}
}
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| class Solution {
public:
int mostWordsFound(vector<string>& sentences) {
int ans = 0;
for (auto& s : sentences) {
int cnt = 1 + count(s.begin(), s.end(), ' ');
ans = max(ans, cnt);
}
return ans;
}
};
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| func mostWordsFound(sentences []string) (ans int) {
for _, s := range sentences {
cnt := 1 + strings.Count(s, " ")
if ans < cnt {
ans = cnt
}
}
return
}
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| function mostWordsFound(sentences: string[]): number {
return sentences.reduce(
(r, s) =>
Math.max(
r,
[...s].reduce((r, c) => r + (c === ' ' ? 1 : 0), 1),
),
0,
);
}
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| impl Solution {
pub fn most_words_found(sentences: Vec<String>) -> i32 {
let mut ans = 0;
for s in sentences.iter() {
let mut count = 1;
for c in s.as_bytes() {
if *c == b' ' {
count += 1;
}
}
ans = ans.max(count);
}
ans
}
}
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| #define max(a, b) (((a) > (b)) ? (a) : (b))
int mostWordsFound(char** sentences, int sentencesSize) {
int ans = 0;
for (int i = 0; i < sentencesSize; i++) {
char* s = sentences[i];
int count = 1;
for (int j = 0; s[j]; j++) {
if (s[j] == ' ') {
count++;
}
}
ans = max(ans, count);
}
return ans;
}
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