Description#
Given an integer n
, return true
if it is a power of four. Otherwise, return false
.
An integer n
is a power of four, if there exists an integer x
such that n == 4x
.
Example 1:
Input: n = 16
Output: true
Example 2:
Input: n = 5
Output: false
Example 3:
Input: n = 1
Output: true
Constraints:
Follow up: Could you solve it without loops/recursion?
Solutions#
Solution 1#
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| class Solution:
def isPowerOfFour(self, n: int) -> bool:
return n > 0 and (n & (n - 1)) == 0 and (n & 0xAAAAAAAA) == 0
|
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| class Solution {
public boolean isPowerOfFour(int n) {
return n > 0 && (n & (n - 1)) == 0 && (n & 0xaaaaaaaa) == 0;
}
}
|
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| class Solution {
public:
bool isPowerOfFour(int n) {
return n > 0 && (n & (n - 1)) == 0 && (n & 0xaaaaaaaa) == 0;
}
};
|
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| func isPowerOfFour(n int) bool {
return n > 0 && (n&(n-1)) == 0 && (n&0xaaaaaaaa) == 0
}
|
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| function isPowerOfFour(n: number): boolean {
return n > 0 && (n & (n - 1)) == 0 && (n & 0xaaaaaaaa) == 0;
}
|
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| /**
* @param {number} n
* @return {boolean}
*/
var isPowerOfFour = function (n) {
return n > 0 && (n & (n - 1)) == 0 && (n & 0xaaaaaaaa) == 0;
};
|