Description#
Design a time-based key-value data structure that can store multiple values for the same key at different time stamps and retrieve the key's value at a certain timestamp.
Implement the TimeMap
class:
TimeMap()
Initializes the object of the data structure.void set(String key, String value, int timestamp)
Stores the key key
with the value value
at the given time timestamp
.String get(String key, int timestamp)
Returns a value such that set
was called previously, with timestamp_prev <= timestamp
. If there are multiple such values, it returns the value associated with the largest timestamp_prev
. If there are no values, it returns ""
.
Example 1:
Input
["TimeMap", "set", "get", "get", "set", "get", "get"]
[[], ["foo", "bar", 1], ["foo", 1], ["foo", 3], ["foo", "bar2", 4], ["foo", 4], ["foo", 5]]
Output
[null, null, "bar", "bar", null, "bar2", "bar2"]
Explanation
TimeMap timeMap = new TimeMap();
timeMap.set("foo", "bar", 1); // store the key "foo" and value "bar" along with timestamp = 1.
timeMap.get("foo", 1); // return "bar"
timeMap.get("foo", 3); // return "bar", since there is no value corresponding to foo at timestamp 3 and timestamp 2, then the only value is at timestamp 1 is "bar".
timeMap.set("foo", "bar2", 4); // store the key "foo" and value "bar2" along with timestamp = 4.
timeMap.get("foo", 4); // return "bar2"
timeMap.get("foo", 5); // return "bar2"
Constraints:
1 <= key.length, value.length <= 100
key
and value
consist of lowercase English letters and digits.1 <= timestamp <= 107
- All the timestamps
timestamp
of set
are strictly increasing. - At most
2 * 105
calls will be made to set
and get
.
Solutions#
Solution 1#
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| class TimeMap:
def __init__(self):
self.ktv = defaultdict(list)
def set(self, key: str, value: str, timestamp: int) -> None:
self.ktv[key].append((timestamp, value))
def get(self, key: str, timestamp: int) -> str:
if key not in self.ktv:
return ''
tv = self.ktv[key]
i = bisect_right(tv, (timestamp, chr(127)))
return tv[i - 1][1] if i else ''
# Your TimeMap object will be instantiated and called as such:
# obj = TimeMap()
# obj.set(key,value,timestamp)
# param_2 = obj.get(key,timestamp)
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| class TimeMap {
private Map<String, TreeMap<Integer, String>> ktv = new HashMap<>();
public TimeMap() {
}
public void set(String key, String value, int timestamp) {
ktv.computeIfAbsent(key, k -> new TreeMap<>()).put(timestamp, value);
}
public String get(String key, int timestamp) {
if (!ktv.containsKey(key)) {
return "";
}
var tv = ktv.get(key);
Integer t = tv.floorKey(timestamp);
return t == null ? "" : tv.get(t);
}
}
/**
* Your TimeMap object will be instantiated and called as such:
* TimeMap obj = new TimeMap();
* obj.set(key,value,timestamp);
* String param_2 = obj.get(key,timestamp);
*/
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| class TimeMap {
public:
TimeMap() {
}
void set(string key, string value, int timestamp) {
ktv[key].emplace_back(timestamp, value);
}
string get(string key, int timestamp) {
auto& pairs = ktv[key];
pair<int, string> p = {timestamp, string({127})};
auto i = upper_bound(pairs.begin(), pairs.end(), p);
return i == pairs.begin() ? "" : (i - 1)->second;
}
private:
unordered_map<string, vector<pair<int, string>>> ktv;
};
/**
* Your TimeMap object will be instantiated and called as such:
* TimeMap* obj = new TimeMap();
* obj->set(key,value,timestamp);
* string param_2 = obj->get(key,timestamp);
*/
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| type TimeMap struct {
ktv map[string][]pair
}
func Constructor() TimeMap {
return TimeMap{map[string][]pair{}}
}
func (this *TimeMap) Set(key string, value string, timestamp int) {
this.ktv[key] = append(this.ktv[key], pair{timestamp, value})
}
func (this *TimeMap) Get(key string, timestamp int) string {
pairs := this.ktv[key]
i := sort.Search(len(pairs), func(i int) bool { return pairs[i].t > timestamp })
if i > 0 {
return pairs[i-1].v
}
return ""
}
type pair struct {
t int
v string
}
/**
* Your TimeMap object will be instantiated and called as such:
* obj := Constructor();
* obj.Set(key,value,timestamp);
* param_2 := obj.Get(key,timestamp);
*/
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